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Functions(p-1) — Maths (commerce) STD 11 Commerce / Arts — Question

Maharashtra BoardEnglish MediumSTD 11 Commerce / ArtsMaths (commerce)Functions(p-1)3 Marks
Question
If $\mathrm{f}(\mathrm{x})=\left\{\begin{array}{cl}4 x-2, & x \leq-3 \\ 5, & -3<x<3, \text { then fmd } \\ x^2, & x \geq 3\end{array}\right.$
(i) $\mathrm{f}(-4)$
(ii) $f(-3)$
(iii) $f(1)$
(iv) $f(5)$
✓

Answer

$
\begin{aligned}
& f(x)=4 x-2, x \leq-3 \\
& =5,-3<x<3 \\
& =x^2, x \geq 3
\end{aligned}
$
(i) $f(-4)=4(-4)-2=-16-2=-18$
(ii) $f(-3)=4(-3)-2=-12-2=-14$
(iii) $f(1)=5$
(iv) $f(5)=5^2=25$

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