Question
If $\mathrm{f}(\mathrm{x})=\left\{\begin{array}{ll}x^2+3, & x \leq 2 \\ 5 x+7, & x>2 \end{array}\right.$},then find$f(3)$
✓
Answer
$ f(x)=x^2+3, x \leq 2$
$=5 x+7, x>2$
$\text { (i) } f(3)=5(3)+7$
$=15+7$
$=22$
$=5 x+7, x>2$
$\text { (i) } f(3)=5(3)+7$
$=15+7$
$=22$
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