Question
If matrix $A = \left[ {\begin{array}{*{20}{c}}3&2&4\\1&2&{ - 1}\\0&1&1\end{array}} \right]$and ${A^{ - 1}} = \frac{1}{K}adj(A),$ then $K$is

Answer

d
(d)$K = \,|A|$; $|A|\,\, = \left| {\,\begin{array}{*{20}{c}}3&2&4\\1&2&{ - 1}\\0&1&1\end{array}\,} \right|\, = \,\,11$.

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