MCQ
If $\mid\text{a}\times\text{b}\mid=4$ and $\mid\text{a.b}\mid=2$ then $\mid{\text{a}}\mid^2\mid{\text{b}}\mid^2$ is equal to:
  • A
    $4$
  • B
    $6$
  • $20$
  • D
    $2$

Answer

Correct option: C.
$20$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Let $f, g$ and $h$ be the real valued functions defined on $R$ as $f(x)=\left\{\begin{array}{cc}\frac{x}{|x|}, & x \neq 0 \\ 1, & x=0\end{array}\right.$,

$g(x)=\left\{\begin{array}{cl}\frac{\sin (x+1)}{(x+1)}, & x \neq-1 \\1, & x=-1\end{array} \text { and } h(x)=2[x]-f(x),\right.$

where $[x]$ is the greatest integer $\leq x$. Then the value of $\lim _{x \rightarrow 1} g(h(x-1))$ is

The point on the curve $y = 6x - x^2$ at which the tangent to the curve is inclined at $\frac{\pi}{4}$ to the line $x + y = 0$ is :
If $\text{A}=\begin{bmatrix}\text{n}&0&0\\0&\text{n}&0\\0&0&\text{n}\end{bmatrix}$ and $\text{B}=\begin{bmatrix}\text{a}_1&\text{a}_2&\text{a}_3\\\text{b}_1&\text{b}_2&\text{b}_3\\\text{c}_1&\text{c}_2&\text{c}_3\end{bmatrix},$ then $AB$ is equal to:
$\int_0^{\pi /2} {\frac{{x\sin x\cos x}}{{{{\cos }^4}x + {{\sin }^4}x}}} \,dx = $
What is the value of $ \cos^{-1}(-\text{x})$ for all $x$ belongs to $[-1, 1]\ ?$
The distance of the point $(-3, 4, 5)$ from the origin:
If $\text{x}=\text{t}^2,\text{y}=\text{t}^3$ Then $\frac{\text{d}^2\text{y}}{\text{dx}^2}=$
The number of critical points of the function $f(x)=(x-2)^{2 / 3}(2 x+1)$ is :
The differential equation of the ellipse $\frac{\text{x}^{2}}{\text{a}^{2}}+\frac{\text{y}^{2}}{\text{b}^{2}}=\text{C}$ is:
Which of the following is(are) $NOT$ the square of a $3 \times 3$ matrix with real entries ?

$[A]$ $\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & -1\end{array}\right]$

$[B]$ $\left[\begin{array}{ccc}-1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -1\end{array}\right]$

$[C]$ $\left[\begin{array}{lll}1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1\end{array}\right]$

$[D]$ $\left[\begin{array}{ccc}1 & 0 & 0 \\ 0 & -1 & 0 \\ 0 & 0 & -1\end{array}\right]$