Question
If (n + 2)! = 60 [(n - 1)!], find n.
(n + 2)! = 60 [(n - 1)!]
(n + 2) (n + 1) (n) (n - 1)! = 60 [(n - 1)!]
$\Rightarrow (\text{n}-2) (\text{n}+1)\text{n}= 5\times 4\times3 $ [By comparing] $\therefore \text{n}= 3$ Hence, n = 3Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Find the middle terms(s) in the expansion of:
$\Big(\frac{\text{p}}{\text{x}}+\frac{\text{x}}{\text{p}}\Big)^{9}$