MCQ
If $n \in N$, then $n\left(n^2-1\right)$ is divisible by:
  • 6
  • B
    16
  • C
    26
  • D
    24

Answer

Correct option: A.
6
  1. 6
Solution:
$n\left(n^2-1\right)=n(n-1)(n+1)$
One of the $n, n+1$ and $n-1$ will be a multiple of 3 .
Since $n-1, n$ and $n+1$ are three consecutive integers, therefore at least one of them will be divisible by 2 .
Therefore $n\left(n^2-1\right)$ is divisible by 6 .

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