MCQ
If nn is a positive integer not a multiple of $3$, then $1+\omega^\text{n}+\omega^{2\text{n}}=$
- A$3$
- B$1$
- ✓$0$
- DNone of these
$1+\omega^\text{n}+\omega^{2\text{n}}$ If n is not a multiple of $31+\omega^\text{n}+\omega^{2\text{n}}=0$
$\because\omega^3=1$ and according to cube-root unity.
$1+\omega^2+\omega=0$
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