MCQ
If $^n{P_3}{ + ^n}{C_{n - 2}} = 14n$, then $n = $
  • $5$
  • B
    $6$
  • C
    $8$
  • D
    $10$

Answer

Correct option: A.
$5$
a
(a) By inspection $n = 5$.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Solution of $\bigg|\text{x}+\frac{1}{\text{x}}\bigg|>2$ is:
$A$ and $B$ toss a coin alternatively, the first to show a head being the winner. If $A$ starts the game, the chance of his winning is
Let $A \left(\frac{3}{\sqrt{ a }}, \sqrt{ a }\right) a >0$, be a fixed point in the $xy$-plane. The image of $A$ in $y$-axis be $B$ and the image of $B$ in $x$-axis be $C$. If $D(3 \cos \theta$, a $\sin \theta)$ is a point in the fourth quadrant such that the maximum area of $\triangle ACD$ is $12$ square units, then $a$ is equal to
If $\alpha$ lies in the second quadrant,then $\sqrt {\frac{{1 - \sin \alpha }}{{1 + \sin \alpha }}}  - \sqrt {\frac{{1 + \sin \alpha }}{{1 - \sin \alpha }}}  =$
$\sin47^\circ+\sin61^\circ-\sin11^\circ-\sin25^\circ$ is equal to
If $\cos \theta - \sin \theta = \sqrt 2 \sin \theta ,$ then $\cos \theta + \sin \theta $ is equal to
A hyperbola having the transverse axis of length $\sqrt{2}$ has the same foci as that of the ellipse $3 x^{2}+4 y^{2}=12,$ then this hyperbola does not pass through which of the following points?
${{\left( -\frac{1}{2}+\frac{\sqrt{3}}{2}i \right)}^{1000}}=$
Let $m, n \in N$ and $\operatorname{gcd}(2, n)=1$. If $30\left(\begin{array}{l}30 \\ 0\end{array}\right)+29\left(\begin{array}{l}30 \\ 1\end{array}\right)+\ldots+2\left(\begin{array}{l}30 \\ 28\end{array}\right)+1\left(\begin{array}{l}30 \\ 29\end{array}\right)= n .2^{ m }$ then $n + m$ is equal to (Here $\left.\left(\begin{array}{l} n \\ k \end{array}\right)={ }^{ n } C _{ k }\right)$
Suppose $\theta $ and $\phi  (\ne 0)$ are such that $sec\,(\theta  + \phi ),$ $sec\,\theta $ and $sec\,(\theta  - \phi )$ are in $A.P.$ If $cos\,\theta  = k\,cos\,( \frac {\phi }{2})$ for some $k,$ then $k$ is equal to