MCQ
If $\omega $ be a complex cube root of unity, then $\left| {\,\begin{array}{*{20}{c}}1&\omega &{ - {\omega ^2}/2}\\1&1&1\\1&{ - 1}&0\end{array}\,} \right| = $
  • $0$
  • B
    $1$
  • C
    $\omega $
  • D
    ${\omega ^2}$

Answer

Correct option: A.
$0$
a
(a) $\left| {\,\begin{array}{*{20}{c}}1&\omega &{ - {\omega ^2}/2}\\1&1&1\\1&{ - 1}&0\end{array}\,} \right| = - \frac{1}{2}\left| {\,\begin{array}{*{20}{c}}1&\omega &{{\omega ^2}}\\1&1&{ - 2}\\1&{ - 1}&0\end{array}\,} \right|$

= $ - \frac{1}{2}\left| {\,\begin{array}{*{20}{c}}0&\omega &{{\omega ^2}}\\0&1&{ - 2}\\0&{ - 1}&0\end{array}\,} \right| = 0$,       (Apply ${C_1} \to {C_1} + {C_2} + {C_3})$.

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