MCQ
If $\omega$ is a complex cube root of unity, then $\frac{1}{\omega}+\frac{1}{\omega^2}$ =
  • A
    1
  • $-1$
  • C
    $\frac{1}{\omega}$
  • D
    $-\frac{1}{\omega}$

Answer

Correct option: B.
$-1$
(B)
$\frac{1}{\omega}+\frac{1}{\omega^2}=\frac{\omega+\omega^2}{\omega^3}=\frac{-1}{1}=-1$

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