If one ball is drawn ar random from each of three boxes containing $3$ white and $1$ black, $2$ white and $2$ black, $1$ white and $3$ black balls, then the probability that $2$ white and $1$ black balls will be drawn is.
A$\frac{13}{32}$
B$\frac{1}{4}$
C$\frac{1}{32}$
D$\frac{3}{16}$
Download our app for free and get started
A$\frac{13}{32}$
Total balls in first box $= 3$ white $+ 1$ black $= 4$
Total balls in second box $= 2$ white $+ 2$ black $= 4$
Total balls in third box $= 1$ white $+ 3$ black $= 4$
Probability of $2$ white and $1$ black
$= P\text{(WWB) + P(WBW) + P(BWW)}$
$=\frac{3}{4}\times\frac{2}{4}\times\frac{3}{4}+\frac{3}{4}\times\frac{2}{4}\times\frac{1}{4}+\frac{1}{4}\times\frac{2}{4}\times\frac{1}{4}$
$=\frac{18+6+2}{64}=\frac{13}{32}$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Choose the correct answer from the given four options.
If $\text{P}(\text{A})=\frac{4}{5},$ and $\text{P}(\text{A}\cap\text{B})=\frac{7}{10},$ then $\text{P}\Big(\frac{\text{B}}{\text{A}}\Big)$ is equal to:
Choose the correct answer from the given four options.A die is thrown and a card is selected at random from a deck of $52$ playing cards. The probability of getting an even number on the die and a spade card is:
Choose the correct answer from the given four options. If $\text{P}(\text{B})=\frac{3}{5},\text{P}\Big(\frac{\text{A}}{\text{B}}\Big)=\frac{1}{2}$ and $\text{P}(\text{A}\cup\text{B})=\frac{4}{5},$ then $\text{P}(\text{A}\cup\text{B})'+\text{P}(\text{A}'\cup\text{B})=$