MCQ
If $| A + B |=| A |+| B |$ the angle between $\overrightarrow A $and $\overrightarrow B$ is $...... ^\circ$
- A$0$
- B$60$
- C$120$
- D$90$
✓
Answer
For two vectors $A \square A \rightarrow$ and $B \square B \rightarrow$, the angle between them being $\theta \theta$,
the magnitude of the resultant vector $A + B \rightarrow A + B \rightarrow$ is given by,
$| A + B |=\sqrt{| A |^2+| B |^2+2 AB \cos \theta}$
Now in the problem we've,
$| A + B |=| A |+| B |$
Squaring on both sides,
$| A + B |^2=(| A |+| B |)^2$
$| A |^2+| B |^2+2| A || B | \cos \theta=| A |^2+| B |^2+2| A || B |$
$\Rightarrow \cos \theta=1$
assuming neither of the vectors are zero vectors.
the magnitude of the resultant vector $A + B \rightarrow A + B \rightarrow$ is given by,
$| A + B |=\sqrt{| A |^2+| B |^2+2 AB \cos \theta}$
Now in the problem we've,
$| A + B |=| A |+| B |$
Squaring on both sides,
$| A + B |^2=(| A |+| B |)^2$
$| A |^2+| B |^2+2| A || B | \cos \theta=| A |^2+| B |^2+2| A || B |$
$\Rightarrow \cos \theta=1$
assuming neither of the vectors are zero vectors.
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