If |3 – 4x| 9, thenx - Vidyadip

MCQ

If $|3 – 4\text{x}|\geq9, $ then$\text{x}\in$

A
$\big(-\infty –3\big)\cup\big(3,\infty\big)$
B
$\big(\infty,\frac{ -3}{2}\big]\cup\big(3 ,\infty\big)$
C
$\big(−\infty ,\frac{-3}{2}\big]\cup\big(0,\infty\big)$
✓
$\big(-\infty,\frac{-3}{2}\big]\cup\big[3,\infty\big)$

✓

Answer

Correct option: D.

$\big(-\infty,\frac{-3}{2}\big]\cup\big[3,\infty\big)$

$\big(-\infty,\frac{-3}{2}\big]\cup\big[3,\infty\big)$

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