MCQ
If $|a + b|\,\, > \,\,|a - b|,$ then the angle between $ a $ and $b$  is
  • Acute
  • B
    Obtuse
  • C
    $\frac{\pi }{2}$
  • D
    $\pi $

Answer

Correct option: A.
Acute
a
(a) $|a + b|\, > \,|a - b|$

Squaring both sides, we get

${a^2} + {b^2} + 2a\,.\,b\, > \,{a^2} + {b^2} - 2a\,.\,b$

$\Rightarrow 4a.b > 0$  $ \Rightarrow \cos \theta  > 0$ Hence $\theta \, < \,90^\circ $

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