MCQ
If $|a + b|\,\, > \,\,|a - b|,$ then the angle between $ a $ and $b$ is
- ✓Acute
- BObtuse
- C$\frac{\pi }{2}$
- D$\pi $
Squaring both sides, we get
${a^2} + {b^2} + 2a\,.\,b\, > \,{a^2} + {b^2} - 2a\,.\,b$
$\Rightarrow 4a.b > 0$ $ \Rightarrow \cos \theta > 0$ Hence $\theta \, < \,90^\circ $
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