- A${\cos ^{ - 1}}\frac{3}{4}$
- ✓${\cos ^{ - 1}}\frac{3}{5}$
- C${\cos ^{ - 1}}\frac{4}{5}$
- D$\frac{\pi }{4}$
and $|a \times b| = ab\,\sin \theta = 4$…..$(ii)$
Dividing $(ii)$ by $(i),$
we get $\tan \theta = \frac{4}{3} \Rightarrow \cos \theta = \frac{3}{5} \Rightarrow \theta = {\cos ^{ - 1}}\frac{3}{5}.$
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$1.$ If $1$ ball is drawn from each of the boxes $B_1, B_2$ and $B_3$, the probability that all $3$ drawn balls are of the same colour is
$(A)$ $\frac{82}{648}$ $(B)$ $\frac{90}{648}$ $(C)$ $\frac{558}{648}$ $(D)$ $\frac{566}{648}$
$2.$ If $2$ balls are drawn (without replacement) from a randomly selected box and one of the balls is white and the other ball is red, the probability that these $2$ balls are drawn from bo $B _2$ is
$(A)$ $\frac{116}{181}$ $(B)$ $\frac{126}{181}$ $(C)$ $\frac{65}{181}$ $(D)$ $\frac{55}{181}$
Give the answer question $1$ and $2.$
$\sum \limits_{k=1}^{10} f(\alpha+k)=\frac{512}{3}\left(2^{20}-1\right)$ holds, is