MCQ
If $|a|\,\, = 3,\,\,\,|b|\,\, = 1,\,\,|c|\,\, = 4$ and $a + b + c = 0,$ then $a\,.\,b + b\,.\,c + c\,.\,a = $
  • $-13$
  • B
    $-10$
  • C
    $13$
  • D
    $10$

Answer

Correct option: A.
$-13$
a
(a) ${(a + b + c)^2} = 0$

==> $|a{|^2} + |b{|^2} + |c{|^2} + 2\,a.b + 2\,b.c + 2\,c.a = 0$

==> $9 + 1 + 16 + 2(a.b + b.c + c.a) = 0$

==> $a.b + b.c + c.a = - \frac{{26}}{2} = - 13.$

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