MCQ
If $|a| + |b|\, = \,|c|$ and $a + b = c,$ then the angle between $ a$ and $ b$ is
- A$\frac{\pi }{2}$
- B$\pi $
- ✓$0$
- DNone of these
and $|a| + |b|\, = \,|c|$ $ \Rightarrow \,|a{|^2} + |b{|^2} + 2|a||b|\, = \,|c{|^2}$
$\therefore \,a\,.\,b = \,|a||b| \Rightarrow \cos \theta = 1$
==> $\theta = 0.$
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