MCQ
If $|\bar{a}+\bar{b}|>|\bar{a}-\bar{b}|$, then the angle between $\bar{a}$ and $\bar{b}$ is
  • Acute
  • B
    Obtuse
  • C
    $\frac{\pi}{2}$
  • D
    $\pi$

Answer

Correct option: A.
Acute
(A) $|\overline{ a }+\overline{ b }|>|\overline{ a }-\overline{ b }|$
Squaring both sides, we get
$\overline{ a }^2+\overline{ b }^2+2 \overline{ a } \cdot \overline{ b }>\overline{ a }^2+\overline{ b }^2-2 \overline{ a } \cdot \overline{ b }$
$\begin{array}{l}\Rightarrow 4 \overline{ a } \cdot \overline{ b }>0 \\ \Rightarrow \cos \theta>0\end{array}$
Hence, $\theta<90^{\circ}$ (acute).

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