Download App

Linear Inequalities — Maths STD 11 Science — Question

CBSE BoardEnglish MediumSTD 11 ScienceMathsLinear Inequalities1 Mark
MCQ
If $|x−1| x - 1 > 5,$ then:
  • A
    $\text{x}\in(-4,6)$
  • B
    $\text{x}\in[-4,6]$
  • ✓
    $\text{x}\in(-\infty,-4)\cup(6,\infty)$
  • D
    $\text{x}\in(-\infty,-4)\cup[6,\infty)$
✓

Answer

Correct option: C.
$\text{x}\in(-\infty,-4)\cup(6,\infty)$
$|x−1| > 5$
$\Rightarrow x − 1 > 5$ or $x − 1 < −5$
$\Rightarrow x > 5 + 1$ or $x < −5 + 1$
$\Rightarrow x > 6$ or $x < −4$
$\Rightarrow\text{x}\in(-\infty,-4)\cup(6,\infty)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Linear Inequalities→Linear Inequalities — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

If $10^n+ 3.4^{n+2}+ k$ is divisible by $9$ for all $n \in N,$ then the least positive integral value of $k$ is:
→
Find the complex number z satisfying the equations $\left| {\frac{{z - 12}}{{z - 8i}}} \right| = \frac{5}{3},\left| {\frac{{z - 4}}{{z - 8}}} \right| = 1$
→
If $X = \{8n - 7n - 1 | n \in N\}$ and $Y = \{49n - 49 | n \in N\}$. Then
→
From $10,000$ lottery tickets numbered from $1$ to $10,000$, one ticket is drawn at random. What is the probability that the number marked on the drawn ticket is divisible by $20$
→
Let $P$ be a point on the parabola, $y^{2}=12 x$ and $N$ be the foot of the perpendicular drawn from $P$ on the axis of the parabola. A line is now drawn through the mid-point $M$ of $PN$, parallel to its axis which meets the parabola at $Q$. If the $y$-intercept of the line $NQ$ is $\frac{4}{3},$ then 
→
Solve the system of inequalities: $-15<\frac{3(x-2)}{5} \leq 0$
→
The sum of the coefficients in the expansion of ${(1 + x - 3{x^2})^{3148}}$ is
→
The number of real values of $x$ for which the equality $\left| {\,3{x^2} + 12x + 6\,} \right| = 5x + 16$ holds good is
→
The incentre of triangle formed by the lines $x = 0,$ $y = 0$ and $3x + 4y = 12$ is
→
If the fourth term of the binomial expansion of $\Big(\text{px}+\big(\frac{1}{\text{x}}\big)\Big)^\text{n}$ is $\frac{5}{2},$ then:
→