MCQ
If $|z|=\max \{|z-2|,|z+2|\}$, then
  • A
    $|z+\bar{z}|=1$
  • B
    $z+\bar{z}=2^2$
  • $|z+\bar{z}|=2$
  • D
    none of these

Answer

Correct option: C.
$|z+\bar{z}|=2$
(C)
$|z|=|z-2| \Rightarrow|z|^2=|z-2|^2$
$\Rightarrow z \overline{ z }=( z -2)(\overline{ z }-2)$
$\Rightarrow z \overline{ z }= z \overline{ z }-2 \overline{ z }-2 z +4$
$\Rightarrow z+\bar{z}=2$ ...(i)
Also, $|z|=|z+2| \Rightarrow|z|^2=|z+2|^2$
$\Rightarrow z \overline{ z }=( z +2)(\overline{ z }+2)$
$=z \bar{z}+2(z+\bar{z})+4$
$\Rightarrow z+\bar{z}=-2$ ...(ii)
From (i) and (ii), we get
$|z+\bar{z}|=2$

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