MCQ
If $p+\frac{1}{p}=x$ and $p-\frac{1}{p}=y$, then the relation between $x$ and $y$ is :
- A$x^2=y^2$
- B$x^2+y^2=4$
- ✓$x^2-y^2=4$
- D$x y=2$
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