MCQ
If $P = \frac{{{A^3}}}{{{B^{5/2}}}}$ and $\Delta A$ is absolute error in $A$ and $\Delta B$ is absolute error in $B$ then absolute error $\Delta P$ in $P$ is
- ✓$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{A} + \frac{5}{2}\frac{{\Delta B}}{B}} \right)P$
- B$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{A} + \frac{5}{2}\frac{{\Delta B}}{B}} \right)$
- C$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{A} - \frac{5}{2}\frac{{\Delta B}}{B}} \right)P$
- D$\Delta P = \pm \left( { 3 \frac{{\Delta A}}{B} - \frac{5}{2}\frac{{\Delta B}}{A}} \right)P$



