Question
If $p_{01}(L) = 90$, and $p_{01}(P) = 40$, find $p_{01}(D – B)$ and $p_{01}(F)$

Answer

$
\begin{aligned}
& p_{01}(L)=90 \quad p_{01}(P)=40 \\
& p_{01}( D - B )=\frac{p_{01}(L)+p_{01}(P)}{2}
\end{aligned}
$
$
\begin{aligned}
& =\frac{90+40}{2} \\
& =65 \\
p_{01}(F) & =\sqrt{P_{01}(L) \times P_{01}(P)} \\
& =\sqrt{90 \times 40} \\
& =60
\end{aligned}
$

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