Download App

Probability — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMathsProbability1 Mark
Question
$\text{If}\ \text{P}(\text{A})=0.8,\ \text{P}(\text{B})=0.5\ \text{and}\ \text{P}(\text{B}|\text{A})=0.4,\ \text{find}:$
$\text{P}(\text{A}\cap\text{B})$
✓

Answer

$\text{P}(\text{A}\cap\text{B})= \text{P}(\text{B}|\text{A}).\text{P}(\text{A})=0.4\times0.8=0.32$​​​​​​​

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "1 Marks" from Probability→Probability — all question types→Maths STD 12 Science question papers→Gujarat Board STD 12 Science question papers→Gujarat Board question paper generator→

Similar questions

Find the projection of the vector $\vec{a}=2 \hat{i}+3 \hat{j}+2 \hat{k}$ on the vector $\vec{b}=\hat{i}+2 \hat{j}+\hat{k}$.
→
Write the degree of the differrntial equation $\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}+\text{e}^{\frac{\text{dy}}{\text{dx}}}=0.$ 
→
The number of all possible matrices of order $3 \times 3$ with each entry 0 or 1 is
→
Integrate the function w.r.t. x: $\frac{\sin \left(\tan ^{-1} x\right)}{1+x^{2}}$
→
Write the degree of the differrntial equation $\Big(1+\frac{\text{dy}}{\text{dx}}\Big)^{3}=\Big(\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}\Big)^{2}.$ 
→
Show the feasible region of the constraints $3 x+5 y \leq 15, x \geq 0, y \geq 0$.
→
For what value of ‘k’ is the function $\text{f(x)} = \begin{cases} \frac{\sin \text{5x}}{\text{3x}} + \cos \text{x}, & \text{if }& \text{x} \neq 0 \\ \text{ }\text{ }\text{ }\text{ } \text{k}, & \text{if } & \text{x = 0}\\ \end{cases}$ continuous at x = 0?
→
Find the area under the given curves and given lines: y = x2, x = 1, x = 2 and x - axis.
→
Compute the following sums:
$\begin{bmatrix}3&-2\\1&4\end{bmatrix}+\begin{bmatrix}-2&4\\1&3\end{bmatrix}$
→
Discuss the continuity of the function $f$, where $f$ is defined by $f(x)=\left\{\begin{array}{ll}-2 & , \text { if } x \leq-1 \\ 2 x & , \text { if }-1 < x \leq 1 \\ 2 & , \text { if } x > 1\end{array}\right.$
→