MCQ
If particles are moving with same velocity, then maximum de-Broglie wavelength will be for
  • A
    Neutron
  • B
    Proton
  • $\beta$- particle
  • D
    $\alpha $- particle

Answer

Correct option: C.
$\beta$- particle
c
(c) $\lambda = \frac{h}{{mv}} \Rightarrow \lambda \propto \frac{1}{m}$

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