Question
If $p+\frac{1}{p}=6 ;$ find $: p^4+\frac{1}{p^4}$
✓
Answer
$\left(p^2+\frac{1}{p^2}\right)$
$ =p^4+\frac{1}{p^4}+2$
$ =(34)^2$
$=p^4+\frac{1}{p^4}+2$
$=p^4+\frac{1}{p^4} $
$ =1158-2 $
$=1154 .$
$ =p^4+\frac{1}{p^4}+2$
$ =(34)^2$
$=p^4+\frac{1}{p^4}+2$
$=p^4+\frac{1}{p^4} $
$ =1158-2 $
$=1154 .$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Rationalise the denominator of the following:
$\frac{1}{(2 \sqrt{5}-\sqrt{3})}$
→$\frac{1}{(2 \sqrt{5}-\sqrt{3})}$
The radii of two circles are $25 \ cm$ and $18 \ cm$. Find the radius of the circle which has a circumference equal to the sum of circumferences of these two circles.
→Prove that:
$\frac{\cos A}{\sin \left(90^{\circ}-A\right)}+\frac{\sin A}{\cos \left(90^{\circ}-A\right)}=2$.
→$\frac{\cos A}{\sin \left(90^{\circ}-A\right)}+\frac{\sin A}{\cos \left(90^{\circ}-A\right)}=2$.
In what time will ₹ 5120 amount to ₹ 7290 at $12 \frac{1}{2} \%$ per annum, compounded annually?
→$ABCD$ is a parallelogram whose sides $AB$ and $BC$ are $18\ cm$ and $12\ cm$ respectively. $G$ is a point on $AC$ such that $CG : GA = 3 : 5 BG$ is produced to meet $CD$ at $Q$ and $AD$ produced at $P.$ Prove that $\triangle CGB \sim \triangle AGP.$ Hence, fi $AP.$
→Name the greatest and the smallest sides in the following triangles$:\triangle ABC, \angle = 56^\circ , \angle B = 64^\circ$ and $\angle C = 60^\circ .$
→Solve for n:
$\left(3^n \times 9^{n+1}\right) \div\left(3^{n-1} \times 27^{n-1}\right)=81$
→$\left(3^n \times 9^{n+1}\right) \div\left(3^{n-1} \times 27^{n-1}\right)=81$
Find the circumference and area of a circle of radius 15 cm. (Take $\pi$) = 3.14 )
→Find the value of $x$ in the following: $2 \sin 3 x=\sqrt{3}$
→Calculate the $\text{C.I.}$ on $Rs. 3,500$ at $6\%$ per annum for $3$ years, the interest being compounded half$-$yearly.
Do not use mathematical tables. Use the necessary information from the following:
$(1.06)^3=1.191016; (1.03)^3= 1.092727$
$(1.06)^6=1.418519; (1.03)^6= 1.194052$
→Do not use mathematical tables. Use the necessary information from the following:
$(1.06)^3=1.191016; (1.03)^3= 1.092727$
$(1.06)^6=1.418519; (1.03)^6= 1.194052$