MCQ
If $\phi (x) = {a^x}$, then ${\{ \phi (p)\} ^3} $ is equal to
- ✓$\phi (3p)$
- B$3\phi (p)$
- C$6\phi (p)$
- D$2\phi (p)$
$\therefore \,\,\,{[\phi \,(p)]^3} = {[{a^p}]^3} = {a^{3p}} = \phi \,(3p)$
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