Question
If $p(x) = 4x^3 - 3x^2 + 2x - 4$ find the remainderwhen p(x) is divided by:
$x + 2$

Answer

$p(x) = 4x^3 - 3x^2 + 2x - 4 ...(i)$
By the remainder theorem the required remainder $= p(2).$
Put $x = -2$ in equation $(i)$, we get
$p(-2) = 4(-2)^3 -3(-2)^2 + 2(-2)-4$
$= 4 x (-8) -3 x 4 -4 -4$
$= -32 -12 -4 -4$
$= -52$
Hence, the remainder is $-52.$

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