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Factorization — Mathematics STD 10 — Question

ICSE BoardEnglish MediumSTD 10MathematicsFactorization2 Marks
Question
If $p(x) = 4x^3 - 3x^2 + 2x - 4$ find the remainderwhen $p(x)$ is divided by:
$x - 4$
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Answer

$p(x) = 4x^3- 3x^2 + 2x - 4 ...(i)$
Put $x = 4$ in equation $(i)$, we get
$p(4) = 4(4)^3 - 3(4)^2 + 2(4) - 4$
$= 4 x 64 -3 x 16 + 8 - 4$
$= 256 - 48 + 8 - 4$
$= 264 - 52$
$= 212$
Hence, the remainder is $212.$

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