If p(x)=x^2-22x+1, than p(22) is equal to: - Vidyadip

Question

If $\text{p}(\text{x})=\text{x}^2-2\sqrt{2}\text{x}+1,$ than $\text{p}(2\sqrt{2})$ is equal to:

✓

Answer

$1$
Solution:
$\text{p}(\text{x})=\text{x}^2-2\sqrt{2}\text{x}+1,$
$\Rightarrow\text{p}(2\sqrt{2})=(2\sqrt{2})^2-2\sqrt{2}(2\sqrt{2})+1$
$\Rightarrow\text{p}(2\sqrt{2})=8-8+1$
$\Rightarrow\text{p}(2\sqrt{2})=1$

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