Question
If p(y) = $4 - 3y -y^2 + 5y^3$, find:
- $p(0)$
- $p(2)$
- $p(-1)$
✓
Answer
- $p(y) = 4 - 3y -y^2 + 5y^3$
$= (4 + 0 - 0 + 0)$
$= 4$
- $p(y) = 4 - 3y -y^2 + 5y^3$
$= (4 + 6 - 4 + 40)$
$= 46$
- $p(y) = 4 - 3y -y^2 + 5y^3$
$= (4 - 3 - 1 - 5)$
$= -5$
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