If r = 1 in a G.P. then what is the sum to n terms? - Vidyadip

MCQ

If $r = 1$ in a $G.P.$ then what is the sum to $n$ terms?

✓
$n\times a$
B
$\frac{\text{a}}{\text{n}}$
C
$(n-1) a$
D
$(n+1) a$

✓

Answer

Correct option: A.

$n\times a$

If a is the first term of $G.P.,$ then $G.P.$
look like $a, a, a, a, …………$
Then sum to n terms becomes $n \times a.$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Sequences and Series→Sequences and Series — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

From the point $(-1, 2)$ tangent lines are drawn to the parabola ${y^2} = 4x$, the area of triangle formed by chord of contact and the tangents is given by

If $x = y\cos \frac{{2\pi }}{3} = z\cos \frac{{4\pi }}{3}$, then $xy + yz + zx = $

If $a,b,c \in Q$, then roots of the equation $(b + c - 2a){x^2} + $ $(c + a - 2b)x + (a + b - 2c) = 0$ are

If in a group of n distinct objects, the number of arrangements of $4$ objects is $12$ times the number of arrangements of $2$ objects, then the number of objects is:

How many words can be made from the letters of the word $DELHI$, if $L$ comes in the middle in every word

The number of irrational terms in the expansion of $\Big(2^{\frac{1}{5}}+3^{\frac{1}{10}}\Big)^{55}$ is:

If $\alpha ,\beta $ be the roots of the equation $2{x^2} - 2({m^2} + 1)x + {m^4} + {m^2} + 1 = 0$, then ${\alpha ^2} + {\beta ^2}$=

The two circles ${x^2} + {y^2} - 2x + 22y + 5 = 0$ and ${x^2} + {y^2} + 14x + 6y + k = 0$ intersect orthogonally provided $k$ is equal to

The value of the limit $\mathop {\lim }\limits_{x \to 0} \,{\left\{ {{1^{\frac{1}{{{{\sin }^2}x}}}} + {2^{\frac{1}{{{{\sin }^2}x}}}} + ....... + {n^{\frac{1}{{{{\sin }^2}x}}}}} \right\}^{{{\sin }^2}x}}$ is

If the equstion $\text{a}_\text{n}\text{x}^\text{n}+\text{a}_\text{n-1}\text{x}^\text{n-1}+...+\text{a}_1\text{x}=0,$
$\text{a}_1\neq0,\text{n}\geq2,$ has positive root $\text{x}=\alpha$ then the eqestions
$\text{na}_\text{n}\text{x}^\text{n-1}+(\text{n-1})\text{a}_\text{n-1}\text{x}^\text{n-2}+...+\text{a}_1=0$ has a positive root, which is: