If {R_1} and {R_2} are respectively the filament resistances of a 200 watt bulb and 100 watt bulb designed to operate on the same voltage,

Q: If ${R_1}$ and ${R_2}$ are respectively the filament resistances of a $200$ $watt$ bulb and $100$ $watt$ bulb designed to operate on the same voltage, then

b (b) $P \propto \frac{1}{R} \Rightarrow \frac{{{P_1}}}{{{P_2}}} = \frac{{{R_2}}}{{{R_1}}}$ $ \Rightarrow \frac{{200}}{{100}} = \frac{{{R_2}}}{{{R_1}}} \Rightarrow {R_2} = 2{R_1}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

If ${R_1}$ and ${R_2}$ are respectively the filament resistances of a $200$ $watt$ bulb and $100$ $watt$ bulb designed to operate on the same voltage, then

A${R_1}$ is two times ${R_2}$
B${R_2}$ is two times ${R_1}$
C${R_2}$ is four times ${R_1}$
D${R_1}$ is four times ${R_2}$

Easy

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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