If resistivity of all four wire connected in parallel is different as given in figure and all other dimensions of wire are same then current $i$ is (resistance of wire having resistivity $\rho $ is $R_0$ )
A$\frac{{23\varepsilon }}{{12{R_0}}}$
B$\frac{{13\varepsilon }}{{12{R_0}}}$
C$\frac{{25\varepsilon }}{{16{R_0}}}$
D$\frac{{13\varepsilon }}{{6{R_0}}}$
Medium
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A$\frac{{23\varepsilon }}{{12{R_0}}}$
a $\mathrm{R}_{0}=\frac{\rho \mathrm{L}}{\mathrm{A}}=\frac{1}{\mathrm{R}}=\frac{1}{\mathrm{R}_{0}}+\frac{1}{2 \mathrm{R}_{0}}+\frac{1}{4 \mathrm{R}_{0}}+\frac{1}{6 \mathrm{R}_{0}}$
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