MCQ
If rth term in the expansion of $\Big(2\text{x}^{2}-\frac{1}{\text{x}}\Big)^{12}$ is without x, then r is equal to:
  • A
    8
  • B
    7
  • 9
  • D
    10

Answer

Correct option: C.
9
rth term in the given expansion is ${^\text{20}}\text{C}_{\text{r}-1}\Big(2\text{x}^{2}\Big)^{12-\text{r}+1}\Big(\frac{-1}{\text{x}}\Big)^{\text{r}-1}$
$=(-1)^{\text{r}-1}\ {^\text{20}}\text{C}_{\text{r}-1}\ 2^{13-\text{r}}\ \text{x}^{26-2\text{r}-\text{r}+1}$
For this term to be independent of x, we must have,
$27-3\text{r}=0$
$\Rightarrow \text{r}=9$
Hence, the term in the expansion is independent.

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