MCQ
If $\sec ^{-1}\left(\frac{1+x}{1-y}\right)=a$, then $\frac{d y}{d x}$ is equal to
- A$\frac{x-1}{y-1}$
- B$\frac{x-1}{y+1}$
- C$\frac{y-1}{x+1}$
- D$\frac{y+1}{x-1}$
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