MCQ
If $\sec \theta+\tan \theta=x$, then $\tan \theta=$
  • A
    $\frac{x^2+1}{x}$
  • B
    $\frac{x^2-1}{x}$
  • C
    $\frac{x^2+1}{2 x}$
  • $\frac{x^2-1}{2 x}$

Answer

Correct option: D.
$\frac{x^2-1}{2 x}$
D

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