Question
If side of a scalene $\triangle$ is doubled then area would be increased by:

Answer

  1. 300%
Solution:
Area of triangle with sides a, b, c $(\text{A})=\sqrt{\text{s}(\text{s}-\text{a})(\text{s}-\text{b})(\text{s}-\text{c})}$
New sides are 2a, 2b and 2c
Then $\text{s}' =\frac{2\text{a}+2\text{b}+2\text{c}}{2}=\text{a}+\text{b}+\text{c}$
$\Rightarrow\text{s}'=2\text{s}\ ...(\text{i})$
New area $=\sqrt{\text{s}'(\text{s}'-2\text{a})(\text{s}'-\text{2b})(\text{s}'-\text{2c})}$
$=\sqrt{2\text{s}(2\text{s}-2\text{a})(2\text{s}-2\text{b})(2\text{s}-2\text{c})}$
$=4\sqrt{\text{s}(\text{s}-\text{a})(\text{s}-\text{b})(\text{s}-\text{c})}$
$=4\text{A}$
Increased area = 4A - A = 3A
% of increased area $=\frac{3\text{A}}{\text{A}}\times100=300\%$

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