MCQ
If ${\sin ^{ - 1}}\frac{1}{2} = {\tan ^{ - 1}}x,$ then $ x =$
- A$\sqrt 3 $
- ✓$\frac{1}{{\sqrt 3 }}$
- C$\frac{1}{{\sqrt 2 }}$
- DNone of these
$ \Rightarrow \,\,{\tan ^{ - 1}}x = \frac{\pi }{6}$
$ \Rightarrow \,\,x = \tan {30^o} = \frac{1}{{\sqrt 3 }}$.
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