MCQ
If ${\sin ^2}x + 2\cos y + xy = 0$, then ${{dy} \over {dx}} = $
- A${{y + 2\sin x} \over {2\sin y + x}}$
- ✓${{y + \sin 2x} \over {2\sin y - x}}$
- C${{y + 2\sin x} \over {\sin y + x}}$
- DNone of these
$ \Rightarrow 2\sin x\cos x - 2\sin y\frac{{dy}}{{dx}} + y + x\frac{{dy}}{{dx}} = 0$
$\therefore \frac{{dy}}{{dx}} = \frac{{y + \sin 2x}}{{2\sin y - x}}$.
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