MCQ
If $\sin 2x + \sin 4x = 2\sin 3x,$ then $x =$
  • $\frac{{n\pi }}{3}$
  • B
    $n\pi + \frac{\pi }{3}$
  • C
    $2n\pi \pm \frac{\pi }{3}$
  • D
    None of these

Answer

Correct option: A.
$\frac{{n\pi }}{3}$
a
(a) $2\sin 3x\cos x - 2\sin 3x = 0$,

$\therefore $ $\sin 3x = 0$, $\cos x = 1$

$\Rightarrow 3x = n\pi $ or $x = \frac{{n\pi }}{3}$ and $x = 2n\pi $

The second value $x = 2n\pi $ is included in the value given by $x = \frac{{n\pi }}{3}$.

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