MCQ
If $\sin A + \cos A = \sqrt 2 ,$ then ${\cos ^2}A = $
  • A
    $\frac{1}{4}$
  • $\frac{1}{2}$
  • C
    $\frac{1}{{\sqrt 2 }}$
  • D
    $\frac{3}{2}$

Answer

Correct option: B.
$\frac{1}{2}$
b
(b) $\sin A + \cos A = \sqrt 2 $. 

On squaring both the sides

==> $1 + \sin 2A = 2\, \Rightarrow \sin 2A = 1 = \sin {90^o}$

==> $2A = {90^o}$ or $A = {45^o}$ 

Now, ${\cos ^2}A = {(\cos {45^o})^2} $

$= {\left( {\frac{1}{{\sqrt 2 }}} \right)^2} = \frac{1}{2}$.

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