MCQ
If $\sin \alpha=\frac{\sqrt{3}}{2}, \cos \beta=\frac{\sqrt{3}}{2}$, then $\tan \alpha \tan \beta$ is
- A$\sqrt{3}$
- B$\frac{1}{\sqrt{3}}$
- ✓1
- D$0$
✓
Answer
Correct option: C.
1
C
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