MCQ
If $\sin \theta+\cos \theta=\sqrt{2}$, then $\tan \theta+\cot \theta=$
  • A
    1
  • 2
  • C
    3
  • D
    4

Answer

Correct option: B.
2
(B)2
$
\begin{array}{l}
\text { We have, } \sin \theta+\cos \theta=\sqrt{2} \\
\Rightarrow \quad(\sin \theta+\cos \theta)^2=2 \\
\Rightarrow \quad \sin ^2 \theta+\cos ^2 \theta+2 \sin \theta \cos \theta=2 \Rightarrow 1+2 \sin \theta \cos \theta=2 \Rightarrow 2 \sin \theta \cos \theta=1 \Rightarrow \sin \theta \cos \theta=\frac{1}{2} \\
\therefore \quad \tan \theta+\cot \theta=\frac{\sin \theta}{\cos \theta}+\frac{\cos \theta}{\sin \theta}=\frac{\sin ^2 \theta+\cos ^2 \theta}{\sin \theta \cos \theta}=\frac{1}{\sin \theta \cos \theta}=2
\end{array}
$

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