Question
If $\sin^2\text{x}+\sin^2\text{ x}=1,$ then write the value of $\cos^8\text{x}+2\cos^6\text{x}+\cos^4\text{ x}.$

Answer

$\sin\text{x}+\sin^2\text{x}=1$ $\sin\text{x}=1-\sin^2\text{x}=\cos^2\text{x}$$\cos^8+2\cos^6\text{x}+\sin^2\text{x}$
$=\sin^4\text{x}+2\sin^3\text{x}+\sin^2\text{x}$
$=(\sin\text{x}+\sin^2\text{x})^2$
$=1$

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