Question
If solid will break under pressure greater than $13\  atm$ and that solid has a specific gravity of $4$ , what is the maximum height of a cylinder made from the solid that can be built at the earth's surface ? (Note: $1\ atm$ = $10^5\  Pa$ .) ......... $m$

Answer

d
$\mathrm{P}_{0} \mathrm{A}+\mathrm{hA} \rho \mathrm{g}=\mathrm{P}_{1} \mathrm{A}$

$\mathrm{h}=\frac{\mathrm{P}_{1}-\mathrm{P}_{0}}{\rho \mathrm{g}}$

$=\frac{12 \times 10^{5}}{4 \times 10^{3} \times 10}=30 \mathrm{m}$

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