If 3 x^2 - 7x - 30 + 2 x^2 - 7x - 5 = x + 5,then x is equal to - Vidyadip

Question

If $\sqrt {3{x^2} - 7x - 30} + \sqrt {2{x^2} - 7x - 5} = x + 5$,then $x$ is equal to

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Answer

c
(c) $\sqrt {3{x^2} - 7x - 30} + \sqrt {2{x^2} - 7x - 5} = x + 5$

$\sqrt {3{x^2} - 7x - 30} = (x + 5) - \sqrt {2{x^2} - 7x - 5} $

on squaring, $\sqrt {2{x^2} - 7x - 5} = 5$

$2{x^2} - 7x - 30 = 0\,\, \Rightarrow \,\,x = 6$.

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