MCQ
If $\sqrt{\sqrt{2500}+\sqrt{961}}=(\text{x})^2,$ then x equals.
- A$81$
- ✓$3$
- C$6561$
- D$9$
✓
Answer
Correct option: B.
$3$
$\sqrt{\sqrt{2500}+\sqrt{961}}=(\text{x})^2....$ Given
$\Rightarrow\sqrt{50+31}=(\text{x})^2$
$\Rightarrow\sqrt{81}=(\text{x})^2$
$\therefore\text{x}^2=9$
$\therefore\text{x}=3$
$\Rightarrow\sqrt{50+31}=(\text{x})^2$
$\Rightarrow\sqrt{81}=(\text{x})^2$
$\therefore\text{x}^2=9$
$\therefore\text{x}=3$
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