Question
If $\sum\limits^{\text{n}}_{\text{r}=1}\text{r}=55,$ find $\sum\limits^{\text{n}}_{\text{r}=1}\text{r}^3$

Answer

$\sum\limits^{\text{n}}_{\text{r}=1}\text{r}=55$ $\Rightarrow\frac{\text{n}(\text{n}+1)}{2}=55\ ...(\text{i})$ Now, $\sum\limits^{\text{n}}_{\text{r}=1}\text{r}^3=\Big[\frac{\text{n}(\text{n}+1)}{2}\Big]^2$ $=\big[55\big]^2$ [Using equation (i), we get] $=3025$ Hence, $\sum\limits^{\text{n}}_{\text{r}=1}\text{r}^3=3025$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free