MCQ
If $\tan A = \frac{1}{2},\tan B = \frac{1}{3},$ then $\cos 2A = $
  • A
    $\sin B$
  • $\sin 2B$
  • C
    $\sin 3B$
  • D
    None of these

Answer

Correct option: B.
$\sin 2B$
b
(b) $A + B = 45^\circ ,$

therefore $2A = 90^\circ - 2B$

$\therefore \cos 2A = \sin 2B$.

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